Base | Representation |
---|---|
bin | 10000110010110010110… |
… | …000001100100101011001 |
3 | 11002022210202002010210011 |
4 | 100302302300030211121 |
5 | 122401443323323413 |
6 | 2242055141121521 |
7 | 146243303653030 |
oct | 20626260144531 |
9 | 4068722063704 |
10 | 1154050214233 |
11 | 405480294a34 |
12 | 1677b50b92a1 |
13 | 84a9899b467 |
14 | 3dbdba9d717 |
15 | 20045bd933d |
hex | 10cb2c0c959 |
1154050214233 has 32 divisors (see below), whose sum is σ = 1394981812224. Its totient is φ = 933369288192.
The previous prime is 1154050214203. The next prime is 1154050214249. The reversal of 1154050214233 is 3324120504511.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1154050214233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1154050214195 and 1154050214204.
It is not an unprimeable number, because it can be changed into a prime (1154050214203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4674066 + ... + 4914772.
It is an arithmetic number, because the mean of its divisors is an integer number (43593181632).
Almost surely, 21154050214233 is an apocalyptic number.
It is an amenable number.
1154050214233 is a deficient number, since it is larger than the sum of its proper divisors (240931597991).
1154050214233 is a wasteful number, since it uses less digits than its factorization.
1154050214233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 241141.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1154050214233 its reverse (3324120504511), we get a palindrome (4478170718744).
The spelling of 1154050214233 in words is "one trillion, one hundred fifty-four billion, fifty million, two hundred fourteen thousand, two hundred thirty-three".
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