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11540953 is a prime number
BaseRepresentation
bin101100000001…
…100111011001
3210201100012201
4230001213121
510423302303
61051210201
7200045044
oct54014731
923640181
1011540953
116572986
123a46961
132511088
141765c5b
15102e81d
hexb019d9

11540953 has 2 divisors, whose sum is σ = 11540954. Its totient is φ = 11540952.

The previous prime is 11540863. The next prime is 11540957. The reversal of 11540953 is 35904511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11370384 + 170569 = 3372^2 + 413^2 .

It is an emirp because it is prime and its reverse (35904511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11540953 is a prime.

It is a super-2 number, since 2×115409532 = 266387192296418, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11540957) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770476 + 5770477.

It is an arithmetic number, because the mean of its divisors is an integer number (5770477).

Almost surely, 211540953 is an apocalyptic number.

It is an amenable number.

11540953 is a deficient number, since it is larger than the sum of its proper divisors (1).

11540953 is an equidigital number, since it uses as much as digits as its factorization.

11540953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2700, while the sum is 28.

The square root of 11540953 is about 3397.1978158476. The cubic root of 11540953 is about 225.9854912763.

The spelling of 11540953 in words is "eleven million, five hundred forty thousand, nine hundred fifty-three".