11541400993 has 2 divisors, whose sum is σ = 11541400994. Its totient is φ = 11541400992.

The previous prime is 11541400991. The next prime is 11541401041. The reversal of 11541400993 is 39900414511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11516079969 + 25321024 = 107313^2 + 5032^2 .

It is an emirp because it is prime and its reverse (39900414511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11541400993 - 2¹ = 11541400991 is a prime.

Together with 11541400991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11541400991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770700496 + 5770700497.

It is an arithmetic number, because the mean of its divisors is an integer number (5770700497).

Almost surely, 2^11541400993 is an apocalyptic number.

It is an amenable number.

11541400993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11541400993 is an equidigital number, since it uses as much as digits as its factorization.

11541400993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 37.

The spelling of 11541400993 in words is "eleven billion, five hundred forty-one million, four hundred thousand, nine hundred ninety-three".