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115440137 = 409928163
BaseRepresentation
bin1101110000101…
…11101000001001
322001012222002122
412320113220021
5214023041022
615242141025
72601140111
oct670275011
9261188078
10115440137
115a18797a
12327b1775
131abbb597
1411490041
15a204742
hex6e17a09

115440137 has 4 divisors (see below), whose sum is σ = 115472400. Its totient is φ = 115407876.

The previous prime is 115440119. The next prime is 115440161. The reversal of 115440137 is 731044511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115440137 - 28 = 115439881 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115440937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9983 + ... + 18180.

It is an arithmetic number, because the mean of its divisors is an integer number (28868100).

Almost surely, 2115440137 is an apocalyptic number.

It is an amenable number.

115440137 is a deficient number, since it is larger than the sum of its proper divisors (32263).

115440137 is an equidigital number, since it uses as much as digits as its factorization.

115440137 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32262.

The product of its (nonzero) digits is 1680, while the sum is 26.

The square root of 115440137 is about 10744.3071903218. The cubic root of 115440137 is about 486.9140179922.

Adding to 115440137 its reverse (731044511), we get a palindrome (846484648).

The spelling of 115440137 in words is "one hundred fifteen million, four hundred forty thousand, one hundred thirty-seven".

Divisors: 1 4099 28163 115440137