Base | Representation |
---|---|
bin | 10000110011001000011… |
… | …011111110110001100101 |
3 | 11002100202002122001121121 |
4 | 100303020123332301211 |
5 | 122403214441413131 |
6 | 2242155214413541 |
7 | 146255312132305 |
oct | 20631033766145 |
9 | 4070662561547 |
10 | 1154414013541 |
11 | 405647684818 |
12 | 167896b012b1 |
13 | 84b26176619 |
14 | 3dc3411d605 |
15 | 20067aeb911 |
hex | 10cc86fec65 |
1154414013541 has 2 divisors, whose sum is σ = 1154414013542. Its totient is φ = 1154414013540.
The previous prime is 1154414013323. The next prime is 1154414013547. The reversal of 1154414013541 is 1453104144511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1149934522500 + 4479491041 = 1072350^2 + 66929^2 .
It is a cyclic number.
It is not a de Polignac number, because 1154414013541 - 219 = 1154413489253 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1154414013497 and 1154414013506.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1154414013547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577207006770 + 577207006771.
It is an arithmetic number, because the mean of its divisors is an integer number (577207006771).
Almost surely, 21154414013541 is an apocalyptic number.
It is an amenable number.
1154414013541 is a deficient number, since it is larger than the sum of its proper divisors (1).
1154414013541 is an equidigital number, since it uses as much as digits as its factorization.
1154414013541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19200, while the sum is 34.
The spelling of 1154414013541 in words is "one trillion, one hundred fifty-four billion, four hundred fourteen million, thirteen thousand, five hundred forty-one".
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