115443113551313 has 2 divisors, whose sum is σ = 115443113551314. Its totient is φ = 115443113551312.

The previous prime is 115443113551309. The next prime is 115443113551343. The reversal of 115443113551313 is 313155311344511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70791744371089 + 44651369180224 = 8413783^2 + 6682168^2 .

It is an emirp because it is prime and its reverse (313155311344511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115443113551313 - 2² = 115443113551309 is a prime.

It is a super-3 number, since 3×115443113551313³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (115443113551343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57721556775656 + 57721556775657.

It is an arithmetic number, because the mean of its divisors is an integer number (57721556775657).

Almost surely, 2^{115443113551313} is an apocalyptic number.

It is an amenable number.

115443113551313 is a deficient number, since it is larger than the sum of its proper divisors (1).

115443113551313 is an equidigital number, since it uses as much as digits as its factorization.

115443113551313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 162000, while the sum is 41.

Adding to 115443113551313 its reverse (313155311344511), we get a palindrome (428598424895824).

The spelling of 115443113551313 in words is "one hundred fifteen trillion, four hundred forty-three billion, one hundred thirteen million, five hundred fifty-one thousand, three hundred thirteen".