Base | Representation |
---|---|
bin | 11010001111111010110001… |
… | …110001100110010111010000 |
3 | 120010202020212001222121110211 |
4 | 122033322301301212113100 |
5 | 110112404444032120222 |
6 | 1045305500105333504 |
7 | 33213326654361631 |
oct | 3217726161462720 |
9 | 503666761877424 |
10 | 115443113551312 |
11 | 33869171005298 |
12 | 10b45795197294 |
13 | 4c55314b17461 |
14 | 207169577b888 |
15 | d52e18838277 |
hex | 68feb1c665d0 |
115443113551312 has 80 divisors (see below), whose sum is σ = 227119954017600. Its totient is φ = 56836948608000.
The previous prime is 115443113551309. The next prime is 115443113551313. The reversal of 115443113551312 is 213155311344511.
It is a super-2 number, since 2×1154431135513122 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115443113551313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2783954803 + ... + 2783996269.
It is an arithmetic number, because the mean of its divisors is an integer number (2838999425220).
Almost surely, 2115443113551312 is an apocalyptic number.
It is an amenable number.
115443113551312 is a deficient number, since it is larger than the sum of its proper divisors (111676840466288).
115443113551312 is a wasteful number, since it uses less digits than its factorization.
115443113551312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49604 (or 49598 counting only the distinct ones).
The product of its digits is 108000, while the sum is 40.
Adding to 115443113551312 its reverse (213155311344511), we get a palindrome (328598424895823).
The spelling of 115443113551312 in words is "one hundred fifteen trillion, four hundred forty-three billion, one hundred thirteen million, five hundred fifty-one thousand, three hundred twelve".
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