Base | Representation |
---|---|
bin | 10101100000010001… |
… | …10101111001110011 |
3 | 1002210121000221001102 |
4 | 22300020311321303 |
5 | 142121012330142 |
6 | 5145334155015 |
7 | 556045146113 |
oct | 126010657163 |
9 | 32717027042 |
10 | 11545042547 |
11 | 499496a385 |
12 | 22a24b2a6b |
13 | 111cb2052c |
14 | 7b742d043 |
15 | 478853532 |
hex | 2b0235e73 |
11545042547 has 2 divisors, whose sum is σ = 11545042548. Its totient is φ = 11545042546.
The previous prime is 11545042513. The next prime is 11545042577. The reversal of 11545042547 is 74524054511.
11545042547 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (74524054511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11545042547 - 28 = 11545042291 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11545042547.
It is not a weakly prime, because it can be changed into another prime (11545042577) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5772521273 + 5772521274.
It is an arithmetic number, because the mean of its divisors is an integer number (5772521274).
Almost surely, 211545042547 is an apocalyptic number.
11545042547 is a deficient number, since it is larger than the sum of its proper divisors (1).
11545042547 is an equidigital number, since it uses as much as digits as its factorization.
11545042547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112000, while the sum is 38.
The spelling of 11545042547 in words is "eleven billion, five hundred forty-five million, forty-two thousand, five hundred forty-seven".
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