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115492691989 is a prime number
BaseRepresentation
bin110101110001111100…
…1101010000000010101
3102001002212212122021201
41223203321222000111
53343012112120424
6125020121112501
711226005453503
oct1534371520025
9361085778251
10115492691989
1144a86682984
121a472328731
13ab774523cc
145838897673
15300e421d44
hex1ae3e6a015

115492691989 has 2 divisors, whose sum is σ = 115492691990. Its totient is φ = 115492691988.

The previous prime is 115492691957. The next prime is 115492691999. The reversal of 115492691989 is 989196294511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112247111089 + 3245580900 = 335033^2 + 56970^2 .

It is a cyclic number.

It is not a de Polignac number, because 115492691989 - 25 = 115492691957 is a prime.

It is a super-2 number, since 2×1154926919892 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 115492691989.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115492691939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57746345994 + 57746345995.

It is an arithmetic number, because the mean of its divisors is an integer number (57746345995).

Almost surely, 2115492691989 is an apocalyptic number.

It is an amenable number.

115492691989 is a deficient number, since it is larger than the sum of its proper divisors (1).

115492691989 is an equidigital number, since it uses as much as digits as its factorization.

115492691989 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12597120, while the sum is 64.

The spelling of 115492691989 in words is "one hundred fifteen billion, four hundred ninety-two million, six hundred ninety-one thousand, nine hundred eighty-nine".