Base | Representation |
---|---|
bin | 1010100000010011110110… |
… | …1001001010111110011111 |
3 | 1111220012002101101201201022 |
4 | 2220010331221022332133 |
5 | 3003214303010340413 |
6 | 40322031134034355 |
7 | 2301321516560246 |
oct | 250047551127637 |
9 | 44805071351638 |
10 | 11550201261983 |
11 | 375345a55457a |
12 | 136660b0489bb |
13 | 65a243c1b377 |
14 | 2bd065b1995d |
15 | 1506a968a608 |
hex | a813da4af9f |
11550201261983 has 2 divisors, whose sum is σ = 11550201261984. Its totient is φ = 11550201261982.
The previous prime is 11550201261971. The next prime is 11550201262043. The reversal of 11550201261983 is 38916210205511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11550201261983 - 230 = 11549127520159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11550201261953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5775100630991 + 5775100630992.
It is an arithmetic number, because the mean of its divisors is an integer number (5775100630992).
Almost surely, 211550201261983 is an apocalyptic number.
11550201261983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11550201261983 is an equidigital number, since it uses as much as digits as its factorization.
11550201261983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 44.
The spelling of 11550201261983 in words is "eleven trillion, five hundred fifty billion, two hundred one million, two hundred sixty-one thousand, nine hundred eighty-three".
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