Base | Representation |
---|---|
bin | 10000110011110001011… |
… | …110000110000001001101 |
3 | 11002102112002000102001211 |
4 | 100303301132012001031 |
5 | 122411122210331412 |
6 | 2242351405534421 |
7 | 146311341453205 |
oct | 20636136060115 |
9 | 4072462012054 |
10 | 1155102433357 |
11 | 405970234814 |
12 | 167a49574411 |
13 | 84c0598cb22 |
14 | 3dc9b721405 |
15 | 200a8282ca7 |
hex | 10cf178604d |
1155102433357 has 2 divisors, whose sum is σ = 1155102433358. Its totient is φ = 1155102433356.
The previous prime is 1155102433343. The next prime is 1155102433369. The reversal of 1155102433357 is 7533342015511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 930711690756 + 224390742601 = 964734^2 + 473699^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1155102433357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1155102433057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577551216678 + 577551216679.
It is an arithmetic number, because the mean of its divisors is an integer number (577551216679).
Almost surely, 21155102433357 is an apocalyptic number.
It is an amenable number.
1155102433357 is a deficient number, since it is larger than the sum of its proper divisors (1).
1155102433357 is an equidigital number, since it uses as much as digits as its factorization.
1155102433357 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 189000, while the sum is 40.
Adding to 1155102433357 its reverse (7533342015511), we get a palindrome (8688444448868).
The spelling of 1155102433357 in words is "one trillion, one hundred fifty-five billion, one hundred two million, four hundred thirty-three thousand, three hundred fifty-seven".
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