Base | Representation |
---|---|
bin | 10000110011110010001… |
… | …110001100011010001111 |
3 | 11002102112221202000111011 |
4 | 100303302032030122033 |
5 | 122411133422324242 |
6 | 2242352540110051 |
7 | 146311553600332 |
oct | 20636216143217 |
9 | 4072487660434 |
10 | 1155115042447 |
11 | 405977367153 |
12 | 167a51835327 |
13 | 84c08486122 |
14 | 3dc9d284619 |
15 | 200a9423d17 |
hex | 10cf238c68f |
1155115042447 has 2 divisors, whose sum is σ = 1155115042448. Its totient is φ = 1155115042446.
The previous prime is 1155115042429. The next prime is 1155115042517. The reversal of 1155115042447 is 7442405115511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1155115042447 - 239 = 605359228559 is a prime.
It is a super-2 number, since 2×11551150424472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1155115040447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577557521223 + 577557521224.
It is an arithmetic number, because the mean of its divisors is an integer number (577557521224).
Almost surely, 21155115042447 is an apocalyptic number.
1155115042447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1155115042447 is an equidigital number, since it uses as much as digits as its factorization.
1155115042447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112000, while the sum is 40.
The spelling of 1155115042447 in words is "one trillion, one hundred fifty-five billion, one hundred fifteen million, forty-two thousand, four hundred forty-seven".
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