Base | Representation |
---|---|
bin | 11010010000111010011111… |
… | …010011011110100111110101 |
3 | 120010222210102122200220002202 |
4 | 122100322133103132213311 |
5 | 110120020044411022013 |
6 | 1045401132224314245 |
7 | 33221301140325056 |
oct | 3220723723364765 |
9 | 503883378626082 |
10 | 115511523142133 |
11 | 33895186486408 |
12 | 10b56aa7472985 |
13 | 4c5b8c7906591 |
14 | 2074b0507872d |
15 | d54abe4e1858 |
hex | 690e9f4de9f5 |
115511523142133 has 16 divisors (see below), whose sum is σ = 123095296301184. Its totient is φ = 108017644116480.
The previous prime is 115511523142129. The next prime is 115511523142157. The reversal of 115511523142133 is 331241325115511.
It is a cyclic number.
It is not a de Polignac number, because 115511523142133 - 22 = 115511523142129 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115511523142033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33184985 + ... + 36500222.
It is an arithmetic number, because the mean of its divisors is an integer number (7693456018824).
Almost surely, 2115511523142133 is an apocalyptic number.
It is an amenable number.
115511523142133 is a deficient number, since it is larger than the sum of its proper divisors (7583773159051).
115511523142133 is a wasteful number, since it uses less digits than its factorization.
115511523142133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69685852.
The product of its digits is 54000, while the sum is 38.
Adding to 115511523142133 its reverse (331241325115511), we get a palindrome (446752848257644).
The spelling of 115511523142133 in words is "one hundred fifteen trillion, five hundred eleven billion, five hundred twenty-three million, one hundred forty-two thousand, one hundred thirty-three".
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