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115515451421471 is a prime number
BaseRepresentation
bin11010010000111110001001…
…011100101011001100011111
3120011000011120102110011022002
4122100332021130223030133
5110120101121030441341
61045403022113112515
733221500400210363
oct3220761134531437
9504004512404262
10115515451421471
1133896911933862
1210b57802b5873b
134c5c0a270621a
142074d98a7d2a3
15d54c4e2eb29b
hex690f8972b31f

115515451421471 has 2 divisors, whose sum is σ = 115515451421472. Its totient is φ = 115515451421470.

The previous prime is 115515451421449. The next prime is 115515451421543. The reversal of 115515451421471 is 174124154515511.

It is a weak prime.

It is an emirp because it is prime and its reverse (174124154515511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115515451421471 is a prime.

It is a super-3 number, since 3×1155154514214713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115515451421431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57757725710735 + 57757725710736.

It is an arithmetic number, because the mean of its divisors is an integer number (57757725710736).

Almost surely, 2115515451421471 is an apocalyptic number.

115515451421471 is a deficient number, since it is larger than the sum of its proper divisors (1).

115515451421471 is an equidigital number, since it uses as much as digits as its factorization.

115515451421471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 560000, while the sum is 47.

The spelling of 115515451421471 in words is "one hundred fifteen trillion, five hundred fifteen billion, four hundred fifty-one million, four hundred twenty-one thousand, four hundred seventy-one".