Base | Representation |
---|---|
bin | 1010100000011100000011… |
… | …0001101001110000110101 |
3 | 1111220101202201011021020120 |
4 | 2220013000301221300311 |
5 | 3003233304213104113 |
6 | 40323033324322153 |
7 | 2301430162566642 |
oct | 250070061516065 |
9 | 44811681137216 |
10 | 11552401300533 |
11 | 3754389400055 |
12 | 1366b239a3359 |
13 | 65a504964422 |
14 | 2bd1d3da6dc9 |
15 | 1507878b3a23 |
hex | a81c0c69c35 |
11552401300533 has 8 divisors (see below), whose sum is σ = 15445172312448. Its totient is φ = 7680615577824.
The previous prime is 11552401300487. The next prime is 11552401300537. The reversal of 11552401300533 is 33500310425511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11552401300533 - 28 = 11552401300277 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11552401300494 and 11552401300503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11552401300537) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5246321016 + ... + 5246323217.
It is an arithmetic number, because the mean of its divisors is an integer number (1930646539056).
Almost surely, 211552401300533 is an apocalyptic number.
It is an amenable number.
11552401300533 is a deficient number, since it is larger than the sum of its proper divisors (3892771011915).
11552401300533 is a wasteful number, since it uses less digits than its factorization.
11552401300533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10492644603.
The product of its (nonzero) digits is 27000, while the sum is 33.
The spelling of 11552401300533 in words is "eleven trillion, five hundred fifty-two billion, four hundred one million, three hundred thousand, five hundred thirty-three".
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