115532452313041 has 4 divisors (see below), whose sum is σ = 120555602413632. Its totient is φ = 110509302212452.

The previous prime is 115532452313039. The next prime is 115532452313077. The reversal of 115532452313041 is 140313254235511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115532452313041 - 2¹ = 115532452313039 is a prime.

It is a super-2 number, since 2×115532452313041² (a number of 29 digits) contains 22 as substring.

It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115532452312985 and 115532452313003.

It is not an unprimeable number, because it can be changed into a prime (115532452313011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2511575050261 + ... + 2511575050306.

It is an arithmetic number, because the mean of its divisors is an integer number (30138900603408).

Almost surely, 2^{115532452313041} is an apocalyptic number.

It is an amenable number.

115532452313041 is a deficient number, since it is larger than the sum of its proper divisors (5023150100591).

115532452313041 is an equidigital number, since it uses as much as digits as its factorization.

115532452313041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5023150100590.

The product of its (nonzero) digits is 216000, while the sum is 40.

The spelling of 115532452313041 in words is "one hundred fifteen trillion, five hundred thirty-two billion, four hundred fifty-two million, three hundred thirteen thousand, forty-one".