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1155340218157 = 1960807379903
BaseRepresentation
bin10000110011111111101…
…001001010111100101101
311002110010122110010111021
4100303333221022330231
5122412114043440112
62242431142254141
7146320256551306
oct20637751127455
94073118403437
101155340218157
11405a82484a84
12167ab5127351
1384c430165a8
143dcc113b7ad
15200be0a2907
hex10cffa4af2d

1155340218157 has 4 divisors (see below), whose sum is σ = 1216147598080. Its totient is φ = 1094532838236.

The previous prime is 1155340218121. The next prime is 1155340218167. The reversal of 1155340218157 is 7518120435511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1155340218157 - 211 = 1155340216109 is a prime.

It is a super-2 number, since 2×11553402181572 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1155340218167) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30403689933 + ... + 30403689970.

It is an arithmetic number, because the mean of its divisors is an integer number (304036899520).

Almost surely, 21155340218157 is an apocalyptic number.

It is an amenable number.

1155340218157 is a deficient number, since it is larger than the sum of its proper divisors (60807379923).

1155340218157 is an equidigital number, since it uses as much as digits as its factorization.

1155340218157 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60807379922.

The product of its (nonzero) digits is 168000, while the sum is 43.

The spelling of 1155340218157 in words is "one trillion, one hundred fifty-five billion, three hundred forty million, two hundred eighteen thousand, one hundred fifty-seven".

Divisors: 1 19 60807379903 1155340218157