11553420433 has 2 divisors, whose sum is σ = 11553420434. Its totient is φ = 11553420432.

The previous prime is 11553420397. The next prime is 11553420469. The reversal of 11553420433 is 33402435511.

It is a balanced prime because it is at equal distance from previous prime (11553420397) and next prime (11553420469).

It can be written as a sum of positive squares in only one way, i.e., 10017407569 + 1536012864 = 100087^2 + 39192^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11553420433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11553420395 and 11553420404.

It is not a weakly prime, because it can be changed into another prime (11553420833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5776710216 + 5776710217.

It is an arithmetic number, because the mean of its divisors is an integer number (5776710217).

Almost surely, 2^11553420433 is an apocalyptic number.

It is an amenable number.

11553420433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11553420433 is an equidigital number, since it uses as much as digits as its factorization.

11553420433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 11553420433 its reverse (33402435511), we get a palindrome (44955855944).

The spelling of 11553420433 in words is "eleven billion, five hundred fifty-three million, four hundred twenty thousand, four hundred thirty-three".