Base | Representation |
---|---|
bin | 1010100000100010100010… |
… | …0111101010011001010110 |
3 | 1111220120021010102210021202 |
4 | 2220020220213222121112 |
5 | 3003300341214342100 |
6 | 40323522242112502 |
7 | 2301521306261051 |
oct | 250105047523126 |
9 | 44816233383252 |
10 | 11554143512150 |
11 | 37550a2884468 |
12 | 136732b34b732 |
13 | 65a7218a0085 |
14 | 2bd31b519a98 |
15 | 15083a8047d5 |
hex | a82289ea656 |
11554143512150 has 12 divisors (see below), whose sum is σ = 21490706932692. Its totient is φ = 4621657404840.
The previous prime is 11554143512143. The next prime is 11554143512209. The reversal of 11554143512150 is 5121534145511.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 115541435072 + ... + 115541435171.
It is an arithmetic number, because the mean of its divisors is an integer number (1790892244391).
Almost surely, 211554143512150 is an apocalyptic number.
11554143512150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11554143512150 is a deficient number, since it is larger than the sum of its proper divisors (9936563420542).
11554143512150 is a wasteful number, since it uses less digits than its factorization.
11554143512150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 231082870255 (or 231082870250 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 38.
Adding to 11554143512150 its reverse (5121534145511), we get a palindrome (16675677657661).
The spelling of 11554143512150 in words is "eleven trillion, five hundred fifty-four billion, one hundred forty-three million, five hundred twelve thousand, one hundred fifty".
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