Base | Representation |
---|---|
bin | 110101110011011100… |
… | …1110001011100100101 |
3 | 102001020101122022010201 |
4 | 1223212321301130211 |
5 | 3343113010212432 |
6 | 125025120350501 |
7 | 11230156520041 |
oct | 1534671613445 |
9 | 361211568121 |
10 | 115543054117 |
11 | 45002050777 |
12 | 1a487175431 |
13 | ab84a0659a |
14 | 5841447021 |
15 | 3013a6dee7 |
hex | 1ae6e71725 |
115543054117 has 2 divisors, whose sum is σ = 115543054118. Its totient is φ = 115543054116.
The previous prime is 115543054093. The next prime is 115543054171. The reversal of 115543054117 is 711450345511.
Together with next prime (115543054171) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60343431201 + 55199622916 = 245649^2 + 234946^2 .
It is a cyclic number.
It is not a de Polignac number, because 115543054117 - 219 = 115542529829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115543054177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57771527058 + 57771527059.
It is an arithmetic number, because the mean of its divisors is an integer number (57771527059).
Almost surely, 2115543054117 is an apocalyptic number.
It is an amenable number.
115543054117 is a deficient number, since it is larger than the sum of its proper divisors (1).
115543054117 is an equidigital number, since it uses as much as digits as its factorization.
115543054117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42000, while the sum is 37.
Adding to 115543054117 its reverse (711450345511), we get a palindrome (826993399628).
The spelling of 115543054117 in words is "one hundred fifteen billion, five hundred forty-three million, fifty-four thousand, one hundred seventeen".
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