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115553100983 = 196790772271
BaseRepresentation
bin110101110011110000…
…0000110010010110111
3102001021002112201211212
41223213200012102313
53343123043212413
6125030115552035
711230341103145
oct1534740062267
9361232481755
10115553100983
1145007793071
121a48a5bb61b
13ab86b13588
145842900595
1530148a5ca8
hex1ae78064b7

115553100983 has 8 divisors (see below), whose sum is σ = 123450289920. Its totient is φ = 107837456760.

The previous prime is 115553100979. The next prime is 115553101003. The reversal of 115553100983 is 389001355511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 115553100983 - 22 = 115553100979 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115553100983.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115553102983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45384863 + ... + 45387408.

It is an arithmetic number, because the mean of its divisors is an integer number (15431286240).

Almost surely, 2115553100983 is an apocalyptic number.

115553100983 is a deficient number, since it is larger than the sum of its proper divisors (7897188937).

115553100983 is an equidigital number, since it uses as much as digits as its factorization.

115553100983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90772357.

The product of its (nonzero) digits is 81000, while the sum is 41.

The spelling of 115553100983 in words is "one hundred fifteen billion, five hundred fifty-three million, one hundred thousand, nine hundred eighty-three".

Divisors: 1 19 67 1273 90772271 1724673149 6081742157 115553100983