Base | Representation |
---|---|
bin | 10000110100001100001… |
… | …010000011100000010101 |
3 | 11002110200021111112102202 |
4 | 100310030022003200111 |
5 | 122413031320240023 |
6 | 2242504042214245 |
7 | 146325416224256 |
oct | 20641412034025 |
9 | 4073607445382 |
10 | 1155550165013 |
11 | 40607aa41182 |
12 | 167b534b4385 |
13 | 84c776741ba |
14 | 3dd00d8cb2d |
15 | 200d2724128 |
hex | 10d0c283815 |
1155550165013 has 2 divisors, whose sum is σ = 1155550165014. Its totient is φ = 1155550165012.
The previous prime is 1155550165009. The next prime is 1155550165061. The reversal of 1155550165013 is 3105610555511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 613938065764 + 541612099249 = 783542^2 + 735943^2 .
It is a cyclic number.
It is not a de Polignac number, because 1155550165013 - 22 = 1155550165009 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1155550165613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577775082506 + 577775082507.
It is an arithmetic number, because the mean of its divisors is an integer number (577775082507).
Almost surely, 21155550165013 is an apocalyptic number.
It is an amenable number.
1155550165013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1155550165013 is an equidigital number, since it uses as much as digits as its factorization.
1155550165013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56250, while the sum is 38.
The spelling of 1155550165013 in words is "one trillion, one hundred fifty-five billion, five hundred fifty million, one hundred sixty-five thousand, thirteen".
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