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115555165005053 is a prime number
BaseRepresentation
bin11010010001100011001000…
…100011111110010011111101
3120011010222002010120020100002
4122101203020203332103331
5110121223434220130203
61045433150541044045
733224404466125034
oct3221431043762375
9504128063506302
10115555165005053
1133901741145a14
1210b63446b56625
134c62a613356c7
142076c851b171b
15d55cc5aa8d88
hex6918c88fe4fd

115555165005053 has 2 divisors, whose sum is σ = 115555165005054. Its totient is φ = 115555165005052.

The previous prime is 115555165005043. The next prime is 115555165005109. The reversal of 115555165005053 is 350500561555511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100429700617444 + 15125464387609 = 10021462^2 + 3889147^2 .

It is an emirp because it is prime and its reverse (350500561555511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115555165005053 - 230 = 115554091263229 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115555165004989 and 115555165005007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115555165005043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57777582502526 + 57777582502527.

It is an arithmetic number, because the mean of its divisors is an integer number (57777582502527).

Almost surely, 2115555165005053 is an apocalyptic number.

It is an amenable number.

115555165005053 is a deficient number, since it is larger than the sum of its proper divisors (1).

115555165005053 is an equidigital number, since it uses as much as digits as its factorization.

115555165005053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1406250, while the sum is 47.

The spelling of 115555165005053 in words is "one hundred fifteen trillion, five hundred fifty-five billion, one hundred sixty-five million, five thousand, fifty-three".