1155571402371 has 8 divisors (see below), whose sum is σ = 1569832848720. Its totient is φ = 755845445472.

The previous prime is 1155571402369. The next prime is 1155571402397. The reversal of 1155571402371 is 1732041755511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1155571402371 - 2¹ = 1155571402369 is a prime.

It is a super-3 number, since 3×1155571402371³ (a number of 37 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1155571402471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3633872176 + ... + 3633872493.

It is an arithmetic number, because the mean of its divisors is an integer number (196229106090).

Almost surely, 2^{1155571402371} is an apocalyptic number.

1155571402371 is a deficient number, since it is larger than the sum of its proper divisors (414261446349).

1155571402371 is an equidigital number, since it uses as much as digits as its factorization.

1155571402371 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7267744725.

The product of its (nonzero) digits is 147000, while the sum is 42.

The spelling of 1155571402371 in words is "one trillion, one hundred fifty-five billion, five hundred seventy-one million, four hundred two thousand, three hundred seventy-one".