Base | Representation |
---|---|
bin | 11010010010100010100110… |
… | …111101010111011101001011 |
3 | 120011101111000000112221011220 |
4 | 122102202212331113131023 |
5 | 110123333030100304120 |
6 | 1045524341550253123 |
7 | 33232336450105032 |
oct | 3222424675273513 |
9 | 504344000487156 |
10 | 115623320713035 |
11 | 33928636281103 |
12 | 10b746a81b71a3 |
13 | 4c693036529b5 |
14 | 207a2acca1719 |
15 | d57964312b40 |
hex | 6928a6f5774b |
115623320713035 has 64 divisors (see below), whose sum is σ = 196497648990720. Its totient is φ = 57893313669120.
The previous prime is 115623320713013. The next prime is 115623320713063. The reversal of 115623320713035 is 530317023326511.
It is not a de Polignac number, because 115623320713035 - 25 = 115623320713003 is a prime.
It is a super-2 number, since 2×1156233207130352 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 11317315 + ... + 18955955.
It is an arithmetic number, because the mean of its divisors is an integer number (3070275765480).
Almost surely, 2115623320713035 is an apocalyptic number.
115623320713035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
115623320713035 is a deficient number, since it is larger than the sum of its proper divisors (80874328277685).
115623320713035 is a wasteful number, since it uses less digits than its factorization.
115623320713035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7639148.
The product of its (nonzero) digits is 340200, while the sum is 42.
The spelling of 115623320713035 in words is "one hundred fifteen trillion, six hundred twenty-three billion, three hundred twenty million, seven hundred thirteen thousand, thirty-five".
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