Base | Representation |
---|---|
bin | 10101100011101110… |
… | …10110100011111001 |
3 | 1002212121112201212210 |
4 | 22301313112203321 |
5 | 142200421342103 |
6 | 5152251125333 |
7 | 556546323444 |
oct | 126167264371 |
9 | 32777481783 |
10 | 11574012153 |
11 | 49aa256700 |
12 | 22b0143849 |
13 | 1125b24502 |
14 | 7bb21065b |
15 | 47b176e03 |
hex | 2b1dd68f9 |
11574012153 has 12 divisors (see below), whose sum is σ = 16962464624. Its totient is φ = 7014552600.
The previous prime is 11574012133. The next prime is 11574012167. The reversal of 11574012153 is 35121047511.
It is not a de Polignac number, because 11574012153 - 29 = 11574011641 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11574012153.
It is not an unprimeable number, because it can be changed into a prime (11574012113) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15941803 + ... + 15942528.
Almost surely, 211574012153 is an apocalyptic number.
It is an amenable number.
11574012153 is a deficient number, since it is larger than the sum of its proper divisors (5388452471).
11574012153 is a wasteful number, since it uses less digits than its factorization.
11574012153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31884356 (or 31884345 counting only the distinct ones).
The product of its (nonzero) digits is 4200, while the sum is 30.
Adding to 11574012153 its reverse (35121047511), we get a palindrome (46695059664).
The spelling of 11574012153 in words is "eleven billion, five hundred seventy-four million, twelve thousand, one hundred fifty-three".
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