Base | Representation |
---|---|
bin | 10000110110100000100… |
… | …100000100010101110011 |
3 | 11002201002210120212121021 |
4 | 100312200210010111303 |
5 | 122433131220342042 |
6 | 2243555104240311 |
7 | 146444211455644 |
oct | 20664044042563 |
9 | 4081083525537 |
10 | 1158040012147 |
11 | 407138440187 |
12 | 168529310097 |
13 | 8528345a325 |
14 | 400999196cb |
15 | 201cb0e6867 |
hex | 10da0904573 |
1158040012147 has 2 divisors, whose sum is σ = 1158040012148. Its totient is φ = 1158040012146.
The previous prime is 1158040012133. The next prime is 1158040012153. The reversal of 1158040012147 is 7412100408511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1158040012147 - 219 = 1158039487859 is a prime.
It is not a weakly prime, because it can be changed into another prime (1158040012187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 579020006073 + 579020006074.
It is an arithmetic number, because the mean of its divisors is an integer number (579020006074).
Almost surely, 21158040012147 is an apocalyptic number.
1158040012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1158040012147 is an equidigital number, since it uses as much as digits as its factorization.
1158040012147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8960, while the sum is 34.
The spelling of 1158040012147 in words is "one trillion, one hundred fifty-eight billion, forty million, twelve thousand, one hundred forty-seven".
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