1158040012133 has 2 divisors, whose sum is σ = 1158040012134. Its totient is φ = 1158040012132.

The previous prime is 1158040012111. The next prime is 1158040012147. The reversal of 1158040012133 is 3312100408511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 980927814724 + 177112197409 = 990418^2 + 420847^2 .

It is an emirp because it is prime and its reverse (3312100408511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1158040012133 - 2¹⁰ = 1158040011109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1158040012096 and 1158040012105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1158040012153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 579020006066 + 579020006067.

It is an arithmetic number, because the mean of its divisors is an integer number (579020006067).

Almost surely, 2^{1158040012133} is an apocalyptic number.

It is an amenable number.

1158040012133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1158040012133 is an equidigital number, since it uses as much as digits as its factorization.

1158040012133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 29.

The spelling of 1158040012133 in words is "one trillion, one hundred fifty-eight billion, forty million, twelve thousand, one hundred thirty-three".