Base | Representation |
---|---|
bin | 110110000000101111… |
… | …1110111010110011011 |
3 | 102002101111020021020101 |
4 | 1230001133313112123 |
5 | 3400021221404022 |
6 | 125141300040231 |
7 | 11244215223046 |
oct | 1540137672633 |
9 | 362344207211 |
10 | 115989247387 |
11 | 452109a7342 |
12 | 1a590693077 |
13 | ac2629c680 |
14 | 58847d3c5d |
15 | 303cd09627 |
hex | 1b017f759b |
115989247387 has 4 divisors (see below), whose sum is σ = 124911497200. Its totient is φ = 107066997576.
The previous prime is 115989247357. The next prime is 115989247417. The reversal of 115989247387 is 783742989511.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 783742989511 = 41 ⋅19115682671.
It is an interprime number because it is at equal distance from previous prime (115989247357) and next prime (115989247417).
It is a cyclic number.
It is not a de Polignac number, because 115989247387 - 215 = 115989214619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (115989247357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4461124887 + ... + 4461124912.
It is an arithmetic number, because the mean of its divisors is an integer number (31227874300).
Almost surely, 2115989247387 is an apocalyptic number.
115989247387 is a deficient number, since it is larger than the sum of its proper divisors (8922249813).
115989247387 is an equidigital number, since it uses as much as digits as its factorization.
115989247387 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8922249812.
The product of its digits is 30481920, while the sum is 64.
The spelling of 115989247387 in words is "one hundred fifteen billion, nine hundred eighty-nine million, two hundred forty-seven thousand, three hundred eighty-seven".
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