Base | Representation |
---|---|
bin | 10101100111000110… |
… | …00111010111110101 |
3 | 1002221120200221200122 |
4 | 22303203013113311 |
5 | 142230134331433 |
6 | 5155140421325 |
7 | 560341411154 |
oct | 126343072765 |
9 | 32846627618 |
10 | 11602261493 |
11 | 4a141a0869 |
12 | 22b96a7845 |
13 | 112b9356b4 |
14 | 7c0c8559b |
15 | 47d8a7198 |
hex | 2b38c75f5 |
11602261493 has 2 divisors, whose sum is σ = 11602261494. Its totient is φ = 11602261492.
The previous prime is 11602261459. The next prime is 11602261511. The reversal of 11602261493 is 39416220611.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7677614884 + 3924646609 = 87622^2 + 62647^2 .
It is a cyclic number.
It is not a de Polignac number, because 11602261493 - 210 = 11602260469 is a prime.
It is a super-2 number, since 2×116022614932 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11608261493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5801130746 + 5801130747.
It is an arithmetic number, because the mean of its divisors is an integer number (5801130747).
Almost surely, 211602261493 is an apocalyptic number.
It is an amenable number.
11602261493 is a deficient number, since it is larger than the sum of its proper divisors (1).
11602261493 is an equidigital number, since it uses as much as digits as its factorization.
11602261493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 11602261493 in words is "eleven billion, six hundred two million, two hundred sixty-one thousand, four hundred ninety-three".
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