Base | Representation |
---|---|
bin | 10101100111001100… |
… | …11000010001011011 |
3 | 1002221122022102102112 |
4 | 22303212120101123 |
5 | 142230344222042 |
6 | 5155211022535 |
7 | 560351603606 |
oct | 126346302133 |
9 | 32848272375 |
10 | 11603117147 |
11 | 4a14725716 |
12 | 22b9a3aa4b |
13 | 112bb74cbb |
14 | 7c102933d |
15 | 47d9c5982 |
hex | 2b399845b |
11603117147 has 2 divisors, whose sum is σ = 11603117148. Its totient is φ = 11603117146.
The previous prime is 11603117143. The next prime is 11603117209. The reversal of 11603117147 is 74171130611.
11603117147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11603117147 - 22 = 11603117143 is a prime.
It is not a weakly prime, because it can be changed into another prime (11603117143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5801558573 + 5801558574.
It is an arithmetic number, because the mean of its divisors is an integer number (5801558574).
Almost surely, 211603117147 is an apocalyptic number.
11603117147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11603117147 is an equidigital number, since it uses as much as digits as its factorization.
11603117147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3528, while the sum is 32.
Adding to 11603117147 its reverse (74171130611), we get a palindrome (85774247758).
The spelling of 11603117147 in words is "eleven billion, six hundred three million, one hundred seventeen thousand, one hundred forty-seven".
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