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116050660555477 is a prime number
BaseRepresentation
bin11010011000110000100110…
…011001011111101011010101
3120012220100001001212012101211
4122120300212121133223111
5110202333223100233402
61050452534254221421
733305245360612354
oct3230604631375325
9505810031765354
10116050660555477
1133a828994a380a
121102348b4b4871
134c9a6b81ac5ab
142092c4c08b99b
15d63b260204d7
hex698c2665fad5

116050660555477 has 2 divisors, whose sum is σ = 116050660555478. Its totient is φ = 116050660555476.

The previous prime is 116050660555397. The next prime is 116050660555483. The reversal of 116050660555477 is 774555066050611.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79215945311556 + 36834715243921 = 8900334^2 + 6069161^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-116050660555477 is a prime.

It is a super-3 number, since 3×1160506605554773 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (116050660558477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58025330277738 + 58025330277739.

It is an arithmetic number, because the mean of its divisors is an integer number (58025330277739).

Almost surely, 2116050660555477 is an apocalyptic number.

It is an amenable number.

116050660555477 is a deficient number, since it is larger than the sum of its proper divisors (1).

116050660555477 is an equidigital number, since it uses as much as digits as its factorization.

116050660555477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26460000, while the sum is 58.

The spelling of 116050660555477 in words is "one hundred sixteen trillion, fifty billion, six hundred sixty million, five hundred fifty-five thousand, four hundred seventy-seven".