Base | Representation |
---|---|
bin | 110110000100000011… |
… | …0110010101001101011 |
3 | 102002200012211221002011 |
4 | 1230020012302221223 |
5 | 3400233112140201 |
6 | 125200300220351 |
7 | 11250032460304 |
oct | 1541006625153 |
9 | 362605757064 |
10 | 116100115051 |
11 | 45268540908 |
12 | 1a60183a6b7 |
13 | ac4324993b |
14 | 58954137ab |
15 | 3047909151 |
hex | 1b081b2a6b |
116100115051 has 2 divisors, whose sum is σ = 116100115052. Its totient is φ = 116100115050.
The previous prime is 116100115013. The next prime is 116100115057. The reversal of 116100115051 is 150511001611.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-116100115051 is a prime.
It is not a weakly prime, because it can be changed into another prime (116100115057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58050057525 + 58050057526.
It is an arithmetic number, because the mean of its divisors is an integer number (58050057526).
Almost surely, 2116100115051 is an apocalyptic number.
116100115051 is a deficient number, since it is larger than the sum of its proper divisors (1).
116100115051 is an equidigital number, since it uses as much as digits as its factorization.
116100115051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 150, while the sum is 22.
Adding to 116100115051 its reverse (150511001611), we get a palindrome (266611116662).
The spelling of 116100115051 in words is "one hundred sixteen billion, one hundred million, one hundred fifteen thousand, fifty-one".
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