Base | Representation |
---|---|
bin | 110110000100000101… |
… | …0010000101011010111 |
3 | 102002200021120010120101 |
4 | 1230020022100223113 |
5 | 3400233330240341 |
6 | 125200331514531 |
7 | 11250043265545 |
oct | 1541012205327 |
9 | 362607503511 |
10 | 116101024471 |
11 | 452690020a3 |
12 | 1a601bb8a47 |
13 | ac434a7863 |
14 | 58955acd95 |
15 | 3047a38831 |
hex | 1b08290ad7 |
116101024471 has 4 divisors (see below), whose sum is σ = 116176269712. Its totient is φ = 116025779232.
The previous prime is 116101024433. The next prime is 116101024511. The reversal of 116101024471 is 174420101611.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 174420101611 = 7 ⋅24917157373.
It is a cyclic number.
It is not a de Polignac number, because 116101024471 - 215 = 116100991703 is a prime.
It is a super-3 number, since 3×1161010244713 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (116101024411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37620306 + ... + 37623391.
It is an arithmetic number, because the mean of its divisors is an integer number (29044067428).
Almost surely, 2116101024471 is an apocalyptic number.
116101024471 is a deficient number, since it is larger than the sum of its proper divisors (75245241).
116101024471 is an equidigital number, since it uses as much as digits as its factorization.
116101024471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75245240.
The product of its (nonzero) digits is 1344, while the sum is 28.
The spelling of 116101024471 in words is "one hundred sixteen billion, one hundred one million, twenty-four thousand, four hundred seventy-one".
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