Base | Representation |
---|---|
bin | 10000111001010001101… |
… | …001111000110100010111 |
3 | 11002222202212020000212001 |
4 | 100321101221320310113 |
5 | 123010222320330142 |
6 | 2245210001140131 |
7 | 146610636364243 |
oct | 20712151706427 |
9 | 4088685200761 |
10 | 1161011105047 |
11 | 408422557262 |
12 | 16901832a647 |
13 | 85637b60171 |
14 | 4029c359423 |
15 | 20301d7a5b7 |
hex | 10e51a78d17 |
1161011105047 has 2 divisors, whose sum is σ = 1161011105048. Its totient is φ = 1161011105046.
The previous prime is 1161011104993. The next prime is 1161011105053. The reversal of 1161011105047 is 7405011101611.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1161011105047 - 27 = 1161011104919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1161011102047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 580505552523 + 580505552524.
It is an arithmetic number, because the mean of its divisors is an integer number (580505552524).
Almost surely, 21161011105047 is an apocalyptic number.
1161011105047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1161011105047 is an equidigital number, since it uses as much as digits as its factorization.
1161011105047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 28.
Adding to 1161011105047 its reverse (7405011101611), we get a palindrome (8566022206658).
The spelling of 1161011105047 in words is "one trillion, one hundred sixty-one billion, eleven million, one hundred five thousand, forty-seven".
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