Base | Representation |
---|---|
bin | 11010011001100111111111… |
… | …110010110101111110101101 |
3 | 120020010000120110111120012010 |
4 | 122121213333302311332231 |
5 | 110204322032430244044 |
6 | 1050540132453231433 |
7 | 33312452366325456 |
oct | 3231477762657655 |
9 | 506100513446163 |
10 | 116110142431149 |
11 | 33aa6042465349 |
12 | 11032b0b932579 |
13 | 4ca31a74a9c29 |
14 | 2095a91bcc12d |
15 | d65458029bb9 |
hex | 6999ffcb5fad |
116110142431149 has 4 divisors (see below), whose sum is σ = 154813523241536. Its totient is φ = 77406761620764.
The previous prime is 116110142431093. The next prime is 116110142431159. The reversal of 116110142431149 is 941134241011611.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 116110142431149 - 211 = 116110142429101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (116110142431159) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19351690405189 + ... + 19351690405194.
It is an arithmetic number, because the mean of its divisors is an integer number (38703380810384).
Almost surely, 2116110142431149 is an apocalyptic number.
It is an amenable number.
116110142431149 is a deficient number, since it is larger than the sum of its proper divisors (38703380810387).
116110142431149 is an equidigital number, since it uses as much as digits as its factorization.
116110142431149 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38703380810386.
The product of its (nonzero) digits is 20736, while the sum is 39.
The spelling of 116110142431149 in words is "one hundred sixteen trillion, one hundred ten billion, one hundred forty-two million, four hundred thirty-one thousand, one hundred forty-nine".
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