Base | Representation |
---|---|
bin | 1010100011111110101111… |
… | …1010100101011000100011 |
3 | 1112010012211200101101201212 |
4 | 2220333223322211120203 |
5 | 3010232421134314243 |
6 | 40411015554020335 |
7 | 2306013163255541 |
oct | 250775372453043 |
9 | 45105750341655 |
10 | 11613254604323 |
11 | 3778176515959 |
12 | 13768875776ab |
13 | 6631821185a8 |
14 | 2c2127cdcd91 |
15 | 152149ebc318 |
hex | a8febea5623 |
11613254604323 has 4 divisors (see below), whose sum is σ = 11613266823288. Its totient is φ = 11613242385360.
The previous prime is 11613254604299. The next prime is 11613254604349. The reversal of 11613254604323 is 32340645231611.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11613254604323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11613254604353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4551386 + ... + 6628847.
It is an arithmetic number, because the mean of its divisors is an integer number (2903316705822).
Almost surely, 211613254604323 is an apocalyptic number.
11613254604323 is a deficient number, since it is larger than the sum of its proper divisors (12218965).
11613254604323 is a wasteful number, since it uses less digits than its factorization.
11613254604323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12218964.
The product of its (nonzero) digits is 311040, while the sum is 41.
Adding to 11613254604323 its reverse (32340645231611), we get a palindrome (43953899835934).
The spelling of 11613254604323 in words is "eleven trillion, six hundred thirteen billion, two hundred fifty-four million, six hundred four thousand, three hundred twenty-three".
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