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11613402654541 = 17987645655343
BaseRepresentation
bin1010100011111111010010…
…1111010110011101001101
31112010020012222222010110021
42220333310233112131031
53010233222034421131
640411042403142141
72306016641545042
oct250776457263515
945106188863407
1011613402654541
113778242046206
121376909074951
136631a69b3b7c
142c213d83b1c9
15152157eb3e11
hexa8ff4bd674d

11613402654541 has 4 divisors (see below), whose sum is σ = 11614048327872. Its totient is φ = 11612756981212.

The previous prime is 11613402654533. The next prime is 11613402654571. The reversal of 11613402654541 is 14545620431611.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11613402654541 - 23 = 11613402654533 is a prime.

It is a super-2 number, since 2×116134026545412 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11613402654571) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 322809685 + ... + 322845658.

It is an arithmetic number, because the mean of its divisors is an integer number (2903512081968).

Almost surely, 211613402654541 is an apocalyptic number.

It is an amenable number.

11613402654541 is a deficient number, since it is larger than the sum of its proper divisors (645673331).

11613402654541 is an equidigital number, since it uses as much as digits as its factorization.

11613402654541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 645673330.

The product of its (nonzero) digits is 345600, while the sum is 43.

The spelling of 11613402654541 in words is "eleven trillion, six hundred thirteen billion, four hundred two million, six hundred fifty-four thousand, five hundred forty-one".

Divisors: 1 17987 645655343 11613402654541