Base | Representation |
---|---|
bin | 1010100011111111110100… |
… | …0101000000111110001001 |
3 | 1112010020120202012121220122 |
4 | 2220333331011000332021 |
5 | 3010234013343121213 |
6 | 40411104321433025 |
7 | 2306023260625514 |
oct | 250777505007611 |
9 | 45106522177818 |
10 | 11613542551433 |
11 | 3778304007879 |
12 | 1376947a9b775 |
13 | 6631c99862b4 |
14 | 2c2154255d7b |
15 | 1521653e9d08 |
hex | a8ffd140f89 |
11613542551433 has 16 divisors (see below), whose sum is σ = 12833967234816. Its totient is φ = 10453010388480.
The previous prime is 11613542551333. The next prime is 11613542551529. The reversal of 11613542551433 is 33415524531611.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11613542551433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11613542551333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1144316 + ... + 4953437.
It is an arithmetic number, because the mean of its divisors is an integer number (802122952176).
Almost surely, 211613542551433 is an apocalyptic number.
It is an amenable number.
11613542551433 is a deficient number, since it is larger than the sum of its proper divisors (1220424683383).
11613542551433 is a wasteful number, since it uses less digits than its factorization.
11613542551433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6102664.
The product of its digits is 648000, while the sum is 44.
The spelling of 11613542551433 in words is "eleven trillion, six hundred thirteen billion, five hundred forty-two million, five hundred fifty-one thousand, four hundred thirty-three".
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