Base | Representation |
---|---|
bin | 1010100100100101000000… |
… | …0011101010101000101001 |
3 | 1112011012100102021022222112 |
4 | 2221021100003222220221 |
5 | 3010414434302010241 |
6 | 40415435024332105 |
7 | 2306525530164425 |
oct | 251112003525051 |
9 | 45135312238875 |
10 | 11623524641321 |
11 | 37815666a973a |
12 | 1378872a74035 |
13 | 66412aa42668 |
14 | 2c281dc75b85 |
15 | 15254b91b1eb |
hex | a92500eaa29 |
11623524641321 has 4 divisors (see below), whose sum is σ = 11624162508672. Its totient is φ = 11622886773972.
The previous prime is 11623524641279. The next prime is 11623524641327. The reversal of 11623524641321 is 12314642532611.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11623524641321 - 214 = 11623524624937 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11623524641327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318906341 + ... + 318942786.
It is an arithmetic number, because the mean of its divisors is an integer number (2906040627168).
Almost surely, 211623524641321 is an apocalyptic number.
It is an amenable number.
11623524641321 is a deficient number, since it is larger than the sum of its proper divisors (637867351).
11623524641321 is an equidigital number, since it uses as much as digits as its factorization.
11623524641321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 637867350.
The product of its digits is 207360, while the sum is 41.
The spelling of 11623524641321 in words is "eleven trillion, six hundred twenty-three billion, five hundred twenty-four million, six hundred forty-one thousand, three hundred twenty-one".
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