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116253273331303 is a prime number
BaseRepresentation
bin11010011011101101010011…
…000011111001011001100111
3120020121201000111112122112021
4122123231103003321121213
5110214143200433100203
61051130003321204011
733326010326030533
oct3233552303713147
9506551014478467
10116253273331303
1134050811096079
12110567b6030607
134cb38378c5864
14209c98d178bc3
15d69033a4a5bd
hex69bb530f9667

116253273331303 has 2 divisors, whose sum is σ = 116253273331304. Its totient is φ = 116253273331302.

The previous prime is 116253273331291. The next prime is 116253273331361. The reversal of 116253273331303 is 303133372352611.

It is a weak prime.

It is an emirp because it is prime and its reverse (303133372352611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 116253273331303 - 229 = 116252736460391 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 116253273331303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (116253273331373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58126636665651 + 58126636665652.

It is an arithmetic number, because the mean of its divisors is an integer number (58126636665652).

Almost surely, 2116253273331303 is an apocalyptic number.

116253273331303 is a deficient number, since it is larger than the sum of its proper divisors (1).

116253273331303 is an equidigital number, since it uses as much as digits as its factorization.

116253273331303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 612360, while the sum is 43.

The spelling of 116253273331303 in words is "one hundred sixteen trillion, two hundred fifty-three billion, two hundred seventy-three million, three hundred thirty-one thousand, three hundred three".