Base | Representation |
---|---|
bin | 10101101001111110… |
… | …11010101100100101 |
3 | 1010000021020020220121 |
4 | 22310333122230211 |
5 | 142302333123033 |
6 | 5201403201541 |
7 | 561054155461 |
oct | 126477325445 |
9 | 33007206817 |
10 | 11626457893 |
11 | 4a26917996 |
12 | 23058162b1 |
13 | 1133957bab |
14 | 7c41834a1 |
15 | 480a8662d |
hex | 2b4fdab25 |
11626457893 has 2 divisors, whose sum is σ = 11626457894. Its totient is φ = 11626457892.
The previous prime is 11626457881. The next prime is 11626457911. The reversal of 11626457893 is 39875462611.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10808097444 + 818360449 = 103962^2 + 28607^2 .
It is a cyclic number.
It is not a de Polignac number, because 11626457893 - 213 = 11626449701 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11626457893.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11626457873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5813228946 + 5813228947.
It is an arithmetic number, because the mean of its divisors is an integer number (5813228947).
Almost surely, 211626457893 is an apocalyptic number.
It is an amenable number.
11626457893 is a deficient number, since it is larger than the sum of its proper divisors (1).
11626457893 is an equidigital number, since it uses as much as digits as its factorization.
11626457893 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2177280, while the sum is 52.
The spelling of 11626457893 in words is "eleven billion, six hundred twenty-six million, four hundred fifty-seven thousand, eight hundred ninety-three".
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