Search a number
-
+
1162931448433 is a prime number
BaseRepresentation
bin10000111011000100000…
…111011010101001110001
311010011201200200120202011
4100323010013122221301
5123023140422322213
62250124320522521
7150006345133066
oct20730407325161
94104650616664
101162931448433
11409218537707
12169473480441
1385882967521
14404013dac6d
15203b575603d
hex10ec41daa71

1162931448433 has 2 divisors, whose sum is σ = 1162931448434. Its totient is φ = 1162931448432.

The previous prime is 1162931448409. The next prime is 1162931448439. The reversal of 1162931448433 is 3348441392611.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 869608470784 + 293322977649 = 932528^2 + 541593^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1162931448433 is a prime.

It is not a weakly prime, because it can be changed into another prime (1162931448439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 581465724216 + 581465724217.

It is an arithmetic number, because the mean of its divisors is an integer number (581465724217).

Almost surely, 21162931448433 is an apocalyptic number.

It is an amenable number.

1162931448433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1162931448433 is an equidigital number, since it uses as much as digits as its factorization.

1162931448433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1492992, while the sum is 49.

The spelling of 1162931448433 in words is "one trillion, one hundred sixty-two billion, nine hundred thirty-one million, four hundred forty-eight thousand, four hundred thirty-three".