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1163025407 is a prime number
BaseRepresentation
bin100010101010010…
…0101101111111111
310000001102210221002
41011110211233333
54340213303112
6311223400515
740551360425
oct10524455777
93001383832
101163025407
11547552225
122855b313b
13156c49a1b
14b0667115
156c1851c2
hex45525bff

1163025407 has 2 divisors, whose sum is σ = 1163025408. Its totient is φ = 1163025406.

The previous prime is 1163025379. The next prime is 1163025421. The reversal of 1163025407 is 7045203611.

It is a strong prime.

It is an emirp because it is prime and its reverse (7045203611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1163025407 - 28 = 1163025151 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1163025407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1163025307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 581512703 + 581512704.

It is an arithmetic number, because the mean of its divisors is an integer number (581512704).

Almost surely, 21163025407 is an apocalyptic number.

1163025407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1163025407 is an equidigital number, since it uses as much as digits as its factorization.

1163025407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 29.

The square root of 1163025407 is about 34103.1583141503. The cubic root of 1163025407 is about 1051.6302436674.

The spelling of 1163025407 in words is "one billion, one hundred sixty-three million, twenty-five thousand, four hundred seven".