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11634478313 is a prime number
BaseRepresentation
bin10101101010111100…
…00000110011101001
31010000211022201212012
422311132000303221
5142311411301223
65202251125305
7561212301563
oct126536006351
933024281765
1011634478313
114a303a5837
122308443835
1311355056c3
147c5270333
1548161cc78
hex2b5780ce9

11634478313 has 2 divisors, whose sum is σ = 11634478314. Its totient is φ = 11634478312.

The previous prime is 11634478301. The next prime is 11634478319. The reversal of 11634478313 is 31387443611.

11634478313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11044328464 + 590149849 = 105092^2 + 24293^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11634478313 is a prime.

It is a super-2 number, since 2×116344783132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11634478319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5817239156 + 5817239157.

It is an arithmetic number, because the mean of its divisors is an integer number (5817239157).

Almost surely, 211634478313 is an apocalyptic number.

It is an amenable number.

11634478313 is a deficient number, since it is larger than the sum of its proper divisors (1).

11634478313 is an equidigital number, since it uses as much as digits as its factorization.

11634478313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 145152, while the sum is 41.

The spelling of 11634478313 in words is "eleven billion, six hundred thirty-four million, four hundred seventy-eight thousand, three hundred thirteen".