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116432510134 = 258216255067
BaseRepresentation
bin110110001101111101…
…0110001110010110110
3102010112101022100102011
41230123322301302312
53401423210311014
6125253252434434
711261210002213
oct1543372616266
9363471270364
10116432510134
1145419131196
121a695018a1a
13ac9707a915
1458c761ab0a
153066bb67c4
hex1b1beb1cb6

116432510134 has 4 divisors (see below), whose sum is σ = 174648765204. Its totient is φ = 58216255066.

The previous prime is 116432510083. The next prime is 116432510143. The reversal of 116432510134 is 431015234611.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1164325101342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 116432510096 and 116432510105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29108127532 + ... + 29108127535.

It is an arithmetic number, because the mean of its divisors is an integer number (43662191301).

Almost surely, 2116432510134 is an apocalyptic number.

116432510134 is a deficient number, since it is larger than the sum of its proper divisors (58216255070).

116432510134 is an equidigital number, since it uses as much as digits as its factorization.

116432510134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58216255069.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 116432510134 its reverse (431015234611), we get a palindrome (547447744745).

The spelling of 116432510134 in words is "one hundred sixteen billion, four hundred thirty-two million, five hundred ten thousand, one hundred thirty-four".

Divisors: 1 2 58216255067 116432510134