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11655540113449 is a prime number
BaseRepresentation
bin1010100110011100010001…
…0101000000000000101001
31112021020222122000211100111
42221213010111000000221
53011431021232112244
640442251535134321
72312041102205341
oct251470425000051
945236878024314
1011655540113449
1137940a5597811
121382b089743a1
1366716083b2cb
142c41b9c45d21
151532c2461e34
hexa99c4540029

11655540113449 has 2 divisors, whose sum is σ = 11655540113450. Its totient is φ = 11655540113448.

The previous prime is 11655540113447. The next prime is 11655540113491. The reversal of 11655540113449 is 94431104555611.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11637786416400 + 17753697049 = 3411420^2 + 133243^2 .

It is a cyclic number.

It is not a de Polignac number, because 11655540113449 - 21 = 11655540113447 is a prime.

Together with 11655540113447, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11655540113443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5827770056724 + 5827770056725.

It is an arithmetic number, because the mean of its divisors is an integer number (5827770056725).

Almost surely, 211655540113449 is an apocalyptic number.

It is an amenable number.

11655540113449 is a deficient number, since it is larger than the sum of its proper divisors (1).

11655540113449 is an equidigital number, since it uses as much as digits as its factorization.

11655540113449 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296000, while the sum is 49.

The spelling of 11655540113449 in words is "eleven trillion, six hundred fifty-five billion, five hundred forty million, one hundred thirteen thousand, four hundred forty-nine".