Base | Representation |
---|---|
bin | 10000111110000001001… |
… | …010101111010001100001 |
3 | 11010110220201220220222120 |
4 | 100332001022233101201 |
5 | 123101134410310103 |
6 | 2251411142454453 |
7 | 150151060524414 |
oct | 20760112572141 |
9 | 4113821826876 |
10 | 1166103213153 |
11 | 40a5a595546a |
12 | 169bb9734429 |
13 | 85c69acb398 |
14 | 40622755b7b |
15 | 204ede28253 |
hex | 10f812af461 |
1166103213153 has 4 divisors (see below), whose sum is σ = 1554804284208. Its totient is φ = 777402142100.
The previous prime is 1166103213139. The next prime is 1166103213179. The reversal of 1166103213153 is 3513123016611.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1166103213153 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1166103213133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194350535523 + ... + 194350535528.
It is an arithmetic number, because the mean of its divisors is an integer number (388701071052).
Almost surely, 21166103213153 is an apocalyptic number.
It is an amenable number.
1166103213153 is a deficient number, since it is larger than the sum of its proper divisors (388701071055).
1166103213153 is an equidigital number, since it uses as much as digits as its factorization.
1166103213153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 388701071054.
The product of its (nonzero) digits is 9720, while the sum is 33.
Adding to 1166103213153 its reverse (3513123016611), we get a palindrome (4679226229764).
The spelling of 1166103213153 in words is "one trillion, one hundred sixty-six billion, one hundred three million, two hundred thirteen thousand, one hundred fifty-three".
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