Base | Representation |
---|---|
bin | 10101101110011111… |
… | …00000011100010001 |
3 | 1010002220022021201111 |
4 | 22313033200130101 |
5 | 142342020331121 |
6 | 5205232533321 |
7 | 562023214633 |
oct | 126717403421 |
9 | 33086267644 |
10 | 11664230161 |
11 | 4a46176841 |
12 | 23163b1241 |
13 | 113b72174c |
14 | 7c91b6a53 |
15 | 4840482e1 |
hex | 2b73e0711 |
11664230161 has 2 divisors, whose sum is σ = 11664230162. Its totient is φ = 11664230160.
The previous prime is 11664230153. The next prime is 11664230167. The reversal of 11664230161 is 16103246611.
11664230161 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8385980625 + 3278249536 = 91575^2 + 57256^2 .
It is a cyclic number.
It is not a de Polignac number, because 11664230161 - 23 = 11664230153 is a prime.
It is not a weakly prime, because it can be changed into another prime (11664230167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5832115080 + 5832115081.
It is an arithmetic number, because the mean of its divisors is an integer number (5832115081).
Almost surely, 211664230161 is an apocalyptic number.
It is an amenable number.
11664230161 is a deficient number, since it is larger than the sum of its proper divisors (1).
11664230161 is an equidigital number, since it uses as much as digits as its factorization.
11664230161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 31.
Adding to 11664230161 its reverse (16103246611), we get a palindrome (27767476772).
The spelling of 11664230161 in words is "eleven billion, six hundred sixty-four million, two hundred thirty thousand, one hundred sixty-one".
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