Base | Representation |
---|---|
bin | 1101111011101… |
… | …11001100000011 |
3 | 22010221010101202 |
4 | 12331313030003 |
5 | 214410131011 |
6 | 15333051415 |
7 | 2616315254 |
oct | 675671403 |
9 | 263833352 |
10 | 116880131 |
11 | 5aa80855 |
12 | 33186b6b |
13 | 1b2a3b54 |
14 | 11746b2b |
15 | a3db23b |
hex | 6f77303 |
116880131 has 2 divisors, whose sum is σ = 116880132. Its totient is φ = 116880130.
The previous prime is 116880109. The next prime is 116880133. The reversal of 116880131 is 131088611.
It is a strong prime.
It is an emirp because it is prime and its reverse (131088611) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-116880131 is a prime.
It is a super-2 number, since 2×1168801312 = 27321930045154322, which contains 22 as substring.
Together with 116880133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 116880094 and 116880103.
It is not a weakly prime, because it can be changed into another prime (116880133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58440065 + 58440066.
It is an arithmetic number, because the mean of its divisors is an integer number (58440066).
Almost surely, 2116880131 is an apocalyptic number.
116880131 is a deficient number, since it is larger than the sum of its proper divisors (1).
116880131 is an equidigital number, since it uses as much as digits as its factorization.
116880131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 29.
The square root of 116880131 is about 10811.1114599749. Note that the first 3 decimals coincide. The cubic root of 116880131 is about 488.9302373564.
The spelling of 116880131 in words is "one hundred sixteen million, eight hundred eighty thousand, one hundred thirty-one".
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